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Include re-roll strategy for rand7

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After seeing the solution that my book advocated, I implemented it using
recursion.
This commit is contained in:
William Carroll 2020-11-14 17:36:04 +00:00
parent 5820f6f459
commit 09cd819a70
1 changed files with 11 additions and 8 deletions
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19
scratch/facebook/moderate/rand7.py
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@ -8,15 +8,18 @@ from collections import Counter
def rand5():
return random.randint(0,4)
def rand4():
x = rand7()
if x >= 4:
return rand4()
return x
# Return [0,6]
def rand7():
def rand7_a():
return sum(rand5() for _ in range(7)) % 7
c = Counter([rand4() for _ in range(100000)])
# Return [0,6]
def rand7_b():
x = 5 * rand5() + rand5()
if x < 21:
return x % 7
return rand7_b()
c = Counter([rand7_a() for _ in range(100000)])
print(c)
c = Counter([rand7_b() for _ in range(100000)])
print(c)