git-subtree-dir: users/wpcarro git-subtree-mainline:464bbcb15cgit-subtree-split:24f5a642afChange-Id: I6105b3762b79126b3488359c95978cadb3efa789
		
			
				
	
	
		
			183 lines
		
	
	
	
		
			4.8 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			183 lines
		
	
	
	
		
			4.8 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
import unittest
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from collections import deque
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from heapq import heappush, heappop
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################################################################################
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# InterviewCake.com
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################################################################################
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# construct_path :: Map String String -> String -> String -> [String]
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def construct_path(paths, beg, end):
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    """
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    Reconstruct the path from `beg` to `end`.
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    """
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    result = []
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    current = end
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    print(paths)
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    print(beg, end)
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    print('-----')
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    while current:
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        result.append(current)
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        current = paths[current]
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    result.reverse()
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    return result
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def get_path_ic(graph, beg, end):
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    """
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    InterviewCake uses a dictionary and back-tracking to store and reconstruct
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    the path instead of storing the path as state on each node.
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    This reduces the memory costs. See get_path_bft for an example of this less
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    optimal solution.
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    """
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    if beg not in graph:
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        raise Exception('Origin node absent from graph.')
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    if end not in graph:
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        raise Exception('Destination node absent from graph.')
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    q = deque()
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    q.append(beg)
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    paths = {beg: None}
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    while q:
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        node = q.popleft()
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        if node == end:
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            print(graph)
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            return construct_path(paths, beg, end)
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        for x in graph[node]:
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            if x not in paths:
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                paths[x] = node
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                q.append(x)
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    return None
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################################################################################
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# Per-node state
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################################################################################
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def get_path_bft(graph, beg, end):
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    """
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    Here we find the shortest path from `beg` to `end` in `graph` by doing a BFT
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    from beg to end and storing the path state alongside each node in the queue.
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    """
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    if beg not in graph:
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        raise Exception('Origin node absent from graph.')
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    if end not in graph:
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        raise Exception('Destination node absent from graph.')
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    q = deque()
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    seen = set()
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    q.append([beg])
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    while q:
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        path = q.popleft()
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        node = path[-1]
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        seen.add(node)
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        if node == end:
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            return path
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        for x in graph[node]:
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            if x not in seen:
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                q.append(path + [x])
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################################################################################
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# Dijkstra's Algorithm
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################################################################################
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def get_path(graph, beg, end):
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    """
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    Here we find the shortest path using Dijkstra's algorithm, which is my
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    favorite solution.
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    """
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    if beg not in graph:
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        raise Exception(
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            'The origin node, {}, is not present in the graph'.format(beg))
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    if end not in graph:
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        raise Exception(
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            'The origin node, {}, is not present in the graph'.format(end))
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    q = []
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    seen = set()
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    heappush(q, (1, [beg]))
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    while q:
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        weight, path = heappop(q)
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        node = path[-1]
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        seen.add(node)
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        if node == end:
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            return path
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        for x in graph[node]:
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            if x not in seen:
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                heappush(q, (weight + 1, path + [x]))
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    return None
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# Tests
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class Test(unittest.TestCase):
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    def setUp(self):
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        self.graph = {
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            'a': ['b', 'c', 'd'],
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            'b': ['a', 'd'],
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            'c': ['a', 'e'],
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            'd': ['b', 'a'],
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            'e': ['c'],
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            'f': ['g'],
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            'g': ['f'],
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        }
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    def test_two_hop_path_1(self):
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        actual = get_path(self.graph, 'a', 'e')
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        expected = ['a', 'c', 'e']
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        self.assertEqual(actual, expected)
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    def test_two_hop_path_2(self):
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        actual = get_path(self.graph, 'd', 'c')
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        expected = ['d', 'a', 'c']
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        self.assertEqual(actual, expected)
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    def test_one_hop_path_1(self):
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        actual = get_path(self.graph, 'a', 'c')
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        expected = ['a', 'c']
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        self.assertEqual(actual, expected)
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    def test_one_hop_path_2(self):
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        actual = get_path(self.graph, 'f', 'g')
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        expected = ['f', 'g']
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        self.assertEqual(actual, expected)
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    def test_one_hop_path_3(self):
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        actual = get_path(self.graph, 'g', 'f')
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        expected = ['g', 'f']
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        self.assertEqual(actual, expected)
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    def test_zero_hop_path(self):
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        actual = get_path(self.graph, 'a', 'a')
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        expected = ['a']
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        self.assertEqual(actual, expected)
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    def test_no_path(self):
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        actual = get_path(self.graph, 'a', 'f')
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        expected = None
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        self.assertEqual(actual, expected)
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    def test_start_node_not_present(self):
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        with self.assertRaises(Exception):
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            get_path(self.graph, 'h', 'a')
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    def test_end_node_not_present(self):
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        with self.assertRaises(Exception):
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            get_path(self.graph, 'a', 'h')
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unittest.main(verbosity=2)
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