Manually merging: - README.md: I added the description from universe/README.md into the heading of dotfiles/README.md. - .envrc: dotfiles/.envrc was a superset of universe/.envrc - .gitignore: Adding some of the ignored patterns from universe/.gitignore to dotfiles/.gitignore Everything else here should be a simple rename.
		
			
				
	
	
		
			49 lines
		
	
	
	
		
			1.8 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			49 lines
		
	
	
	
		
			1.8 KiB
		
	
	
	
		
			Python
		
	
	
	
	
	
from random import choice
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from math import floor
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# Applying Chapter 1 from "Algorithms to Live By", which describes optimal
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# stopping problems. Technically this simulation is invalid because the
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# `candidates` function takes a lower bound and an upper bound, which allows us
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# to know the cardinal number of an individual candidates. The "look then leap"
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# algorithm is ideal for no-information games - i.e. games when upper and lower
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# bounds aren't known. The `look_then_leap/1` function is ignorant of this
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# information, so it behaves as if in a no-information game. Strangely enough,
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# this algorithm will pick the best candidate 37% of the time.
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#
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# Chapter 1 describes two algorithms:
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# 1. Look-then-leap: ordinal numbers - i.e. no-information games. Look-then-leap
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#    finds the best candidate 37% of the time.
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# 2. Threshold: cardinal numbers - i.e. where upper and lower bounds are
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#    known. The Threshold algorithm finds the best candidate ~55% of the time.
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#
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# All of this and more can be studied as "optimal stopping theory". This applies
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# to finding a spouse, parking a car, picking an apartment in a city, and more.
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# candidates :: Int -> Int -> Int -> [Int]
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def candidates(lb, ub, ct):
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    xs = list(range(lb, ub + 1))
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    return [choice(xs) for _ in range(ct)]
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# look_then_leap :: [Integer] -> Integer
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def look_then_leap(candidates):
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    best = candidates[0]
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    seen_ct = 1
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    ignore_ct = floor(len(candidates) * 0.37)
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    for x in candidates[1:]:
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        if ignore_ct > 0:
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            ignore_ct -= 1
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            best = max(best, x)
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        else:
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            if x > best:
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                print('Choosing the {} candidate.'.format(seen_ct))
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                return x
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        seen_ct += 1
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    print('You may have waited too long.')
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    return candidates[-1]
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candidates = candidates(1, 100, 100)
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print(candidates)
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print(look_then_leap(candidates))
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