Solves the InterviewCake.com problem that asks us to write a function that returns the number, y, that occurs twice in a list, xs, where xs is an unsorted list of integers from 1..n with a length of n + 1.
		
			
				
	
	
		
			29 lines
		
	
	
	
		
			656 B
		
	
	
	
		
			Python
		
	
	
	
	
	
			
		
		
	
	
			29 lines
		
	
	
	
		
			656 B
		
	
	
	
		
			Python
		
	
	
	
	
	
import unittest
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def find_repeat(xs):
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    n = max(xs)
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    expected_sum = (n + 1) * n / 2
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    actual_sum = sum(xs)
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    return actual_sum - expected_sum
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# Tests
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class Test(unittest.TestCase):
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    def test_short_list(self):
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        actual = find_repeat([1, 2, 1])
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        expected = 1
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        self.assertEqual(actual, expected)
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    def test_medium_list(self):
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        actual = find_repeat([4, 1, 3, 4, 2])
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        expected = 4
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        self.assertEqual(actual, expected)
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    def test_long_list(self):
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        actual = find_repeat([1, 5, 9, 7, 2, 6, 3, 8, 2, 4])
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        expected = 2
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        self.assertEqual(actual, expected)
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unittest.main(verbosity=2)
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